Y=-16x^2+163x+148

Solution for Y=-16x^2+163x+148 equation:

=-16Y^2+163Y+148

We move all terms to the left:

-(-16Y^2+163Y+148)=0

We get rid of parentheses

16Y^2-163Y-148=0

a = 16; b = -163; c = -148;
Δ = b2-4ac
Δ = -1632-4·16·(-148)
Δ = 36041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-163)-\sqrt{36041}}{2*16}=\frac{163-\sqrt{36041}}{32}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-163)+\sqrt{36041}}{2*16}=\frac{163+\sqrt{36041}}{32}
$